@abakcus
It really is, but interesting that an interval between 0 and 1 results in division of 1 by a value greater than the interval being calculated. I don't understand this completely, but it requires some proportions outside of the interval in order to result in that.
@abakcus
It's not loading I wrote this so I can find it later, there is no other comment besides this comment and the one explaining it, and this comment Im making right now.